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2 years, 3 months ago

Why did the USA men's ice hockey team play Canada twice in the 2010 Winter Olympics?

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matt2024 | 2 years, 3 months ago
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The Olympic Ice Hockey tournament was played in different rounds. The first round was the preliminary, which included 3 groups. Groups A U.S., Switzerland, Canada, and Norway. Group B Russia, Latvia, Czech Republic, and Slovakia. Group C Finland, Belarus, Sweden, and Germany. The preliminary round is a round robbin where each team in the group plays eachother to see who will win the group. The U.S. faced Canada in this round and won 5-3.
The 3 group winners, and a fouth (wild card) automatically move on to the quaterfinals, they wre U.S., Russia, Sweden, and Finland. The other teams then played in a 8 team playoff qualification round. Canada, Switzerland, Slovakia, and Czech Republic moved on to play in the 8 team quaterfinals. U.S. played Switzerland, and Canada played Russia. Both teams won their games and moved to the semifinals, wher the U.S. played Finland, and Canada played Slovakia. They both won those games meaning they would meet in the Gold medal match.
I hope this explained it all well enough. Below is a link to the olympic website, where I got all of my information. It shows how it was all set up.

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mielu_istetz | 2 years, 3 months ago
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They played once in the preliminary round groups. Each group had 4 teams
Canada and US were in Group A along with Switzerland and Norway
Both Canada and US qualified in the upper rounds and they met again in the final

It happens in competitions when there are groups and the winners of the groups advance to the play-offs
for example in the Soccer World Cup
In 2002 Brazil met Turkey twice, once in the group and another time in the semi-final

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