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It seems as though a rule of thumb is 60-80 acres of land per wind turbine. With that in mind it would take roughly 4.62 million to 6.16 million acres of land.
America has about 2.3 billion acres of land with the major uses in 2002 being forest-use land, 651 million acres (28.8 percent); grassland pasture and range land, 587 million acres (25.9 percent); cropland, 442 million acres (19.5 percent); special uses (primarily parks and wildlife areas), 297 million acres (13.1 percent); miscellaneous other uses, 228 million acres (10.1 percent); and urban land, 60 million acres (2.6 percent).
This would make it plausible just by the numbers but probably inefficient because not all land is prime for setting up wind turbines to produce energy. If American were completely flat then we would have probably already gone that route once the technology became efficient enough.
Source(s):
http://www.heritagewindenergy.com/faq.html
http://www.ers.usda.gov/Publications/EIB14/
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cjsexp
According to this article: http://www.usatoday.com/tech/news/2006-02-23-windmills-midwest_x.htm the big windmills in California are 300 feet tall, and judging by some pictures of windmills ( http://www.flickr.com/photos/tags/windmill ), the rotor radius is about half the height of the tower, making the diameter about equal to the height of the tower.
Using this information, we can estimate that placing them 7.5 rotor diameters apart will mean 2250 feet between windmills.
Since we need 77,000 wind towers, and the most efficient use of space is to place them in a square piece of land, we take the square root of 77,000 to find out how many wind towers will be in each row: approximately 278.
So 278 towers multiplied by 2250 feet between them gives us 625,500 feet for each side of our area of land. This is 391,250,250,000 square feet (391 billion square feet), or about 9 million acres, or about 14,000 square miles (about the combined size of Vermont and Connecticut, according to http://www.theus50.com/area.shtml ).
Note that this is all very "back of a napkin" math.
Source(s):
http://www.windpoweringamerica.gov/pdfs/wpa/34600_landowners_faq.pdf
http://www.usatoday.com/tech/news/2006-02-23-windmills-midwest_x.htm
http://www.flickr.com/photos/tags/windmill
http://www.theus50.com/area.shtml
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Answered Question
December 23, 2008 04:24 PM
Given the answer below, how many acres of land would be required for 77,000 wind towers?
The best wind turbine in the world currently are these Enceron towers. Each one produces 6 MW of power. Now if we went to these towers exclusively, just for the sake of argument, it would take approximately 77,306 of these towers, running at full capacity year-round, to power the entire United States.
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Best Answer Chosen by Asker
| December 23, 2008 04:33 PM |
America has about 2.3 billion acres of land with the major uses in 2002 being forest-use land, 651 million acres (28.8 percent); grassland pasture and range land, 587 million acres (25.9 percent); cropland, 442 million acres (19.5 percent); special uses (primarily parks and wildlife areas), 297 million acres (13.1 percent); miscellaneous other uses, 228 million acres (10.1 percent); and urban land, 60 million acres (2.6 percent).
This would make it plausible just by the numbers but probably inefficient because not all land is prime for setting up wind turbines to produce energy. If American were completely flat then we would have probably already gone that route once the technology became efficient enough.
Source(s):
http://www.heritagewindenergy.com/faq.html
http://www.ers.usda.gov/Publications/EIB14/
| Asker's Rating: |
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cjsexp
December 23, 2008 04:39 PM
to put this in perspective, 640 Acres= 1 square mile so 6.16 million acres = 9625 square miles. It will take a LOT of land to be "green"
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Other Answers (1)
December 23, 2008 04:41 PM
According to WindPoweringAmerica.gov's "Landowner Frequently Asked Questions and Answers" ( http://www.windpoweringamerica.gov/pdfs/wpa/34600_landowners_faq.pdf ), wind towers are typically placed 5 to 10 rotor diameters apart. (Let's assume that this distance applies in each direction.) According to this article: http://www.usatoday.com/tech/news/2006-02-23-windmills-midwest_x.htm the big windmills in California are 300 feet tall, and judging by some pictures of windmills ( http://www.flickr.com/photos/tags/windmill ), the rotor radius is about half the height of the tower, making the diameter about equal to the height of the tower.
Using this information, we can estimate that placing them 7.5 rotor diameters apart will mean 2250 feet between windmills.
Since we need 77,000 wind towers, and the most efficient use of space is to place them in a square piece of land, we take the square root of 77,000 to find out how many wind towers will be in each row: approximately 278.
So 278 towers multiplied by 2250 feet between them gives us 625,500 feet for each side of our area of land. This is 391,250,250,000 square feet (391 billion square feet), or about 9 million acres, or about 14,000 square miles (about the combined size of Vermont and Connecticut, according to http://www.theus50.com/area.shtml ).
Note that this is all very "back of a napkin" math.
Source(s):
http://www.windpoweringamerica.gov/pdfs/wpa/34600_landowners_faq.pdf
http://www.usatoday.com/tech/news/2006-02-23-windmills-midwest_x.htm
http://www.flickr.com/photos/tags/windmill
http://www.theus50.com/area.shtml
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