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3 years, 2 months ago

Math whizzes: prove sin x = cos x ( cot x - 2 cot 2x )

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pmacdon1 | 3 years, 2 months ago
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Ok I'm gonna do this as simply as I can.

I found a proof on another website that:
cot 2x = (1/2)(cot x - tan x)
Here is the proof:

(1) cot 2x = 1/tan(2x) = cos(2x)/sin(2x)

(2) cos(2x) = cos^2(x) - sin^2(x)

(3) sin(2x) = 2(sin x)(cos x)

(4) cos(2x)/sin(2x) = (cos^2(x) - sin^2(x))/2(sin x)(cos x) =

= (1/2)(cos(x)/sin(x) - sin(x)/cos(x)) = (1/2)(cot(x) - tan(x))
It explains this more clearly here:
http://mathrefresher.blogspot.com/2008/01/cot-2x-12-tan-x-cot-x.html

So now we have:
cot 2x = (1/2)(cot x - tan x)
tan(x) = sin(x)/cos(x) (by definition)

And the equation we are proving is:

sin x = cos x ( cot x - 2 cot 2x )

So to substitute for cot 2x

sin x = cos x ( cot x - 2 {(1/2)(cot x - tan x)}
sin x = cos x ( cot x - cot x + tan x)
sin x = cos x (tan x)
sin x = cos x (sin x / cos x)
sin x = sin x

I'm really bad at trying to explain math on the internet, but I hope this is understandable.

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