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Average outlets should be able to handle about 16 amps at 110 Volts .
16 x 110 = 1760 Watts
Average lights use about 25 watts per 50-bulb strand.
1760 watts / 25 Watts = 470 strands.
Technically :-)
Your breaker really should kick in, before the outlet blows up.
You're risking a fire if breaker is not working properly.
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In practice it is very dangerous to overload an electrical outlet with too many lights. The often low quality cabling for the lights usually can not withstand the added heat and current for many lights.
We have plugged in 4-5 strands of 100 light cables without any problems into a single outlet. I wouldn't go much beyond that.
Also, keep in mind a single outlet is usually tied to many other outlets all running from one circuit. So that single outlet may also be shared with your TV, microwave, etc.
Safety first.
Source(s):
http://en.wikipedia.org/wiki/Milliamp
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Each electrical circuit in your home has a fuse or circuit breaker, typically rated at 15 Amperes (Amps).
Lights are rated in Watts, and small incandescent Christmas bulbs are usually 2.5 to 3 watts each, while the large, C7 bulbs are 7 watts each. The new LED lights are 4 to 8 watts for a whole string of 100, but are much less bright.
Watts = Amps/Volts, so for a 15 Amp circuit at 110 volts, you could in theory power up to 1650 Watts (15*110) without overloading the circuit, though a margin of at least 10% is recommended for safety, so call it 1500 watts even as the capacity per circuit.
Note that extension cords and timers are marked with a rating in Watts and can dangerously overheat if overloaded.
Source(s):
Wikipedia: Ohm's Law
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Answered Question
December 15, 2008 05:48 PM
How many christmas lights can I plug into one outlet?
I melted an outlet on my house. I have lots of lights pluged into 2 timers. The two timers are then pluged into one outlet.
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Best Answer Chosen by Asker
| December 15, 2008 06:18 PM |
16 x 110 = 1760 Watts
Average lights use about 25 watts per 50-bulb strand.
1760 watts / 25 Watts = 470 strands.
Technically :-)
Your breaker really should kick in, before the outlet blows up.
You're risking a fire if breaker is not working properly.
Permalink | Report
Other Answers (3)
December 15, 2008 05:55 PM
In theory, thousands and thousands since each light only takes a small amount of energy (http://en.wikipedia.org/wiki/Milliamp) In practice it is very dangerous to overload an electrical outlet with too many lights. The often low quality cabling for the lights usually can not withstand the added heat and current for many lights.
We have plugged in 4-5 strands of 100 light cables without any problems into a single outlet. I wouldn't go much beyond that.
Also, keep in mind a single outlet is usually tied to many other outlets all running from one circuit. So that single outlet may also be shared with your TV, microwave, etc.
Safety first.
Source(s):
http://en.wikipedia.org/wiki/Milliamp
Permalink | Report
December 16, 2008 12:30 PM
Here's how to figure it: Each electrical circuit in your home has a fuse or circuit breaker, typically rated at 15 Amperes (Amps).
Lights are rated in Watts, and small incandescent Christmas bulbs are usually 2.5 to 3 watts each, while the large, C7 bulbs are 7 watts each. The new LED lights are 4 to 8 watts for a whole string of 100, but are much less bright.
Watts = Amps/Volts, so for a 15 Amp circuit at 110 volts, you could in theory power up to 1650 Watts (15*110) without overloading the circuit, though a margin of at least 10% is recommended for safety, so call it 1500 watts even as the capacity per circuit.
Note that extension cords and timers are marked with a rating in Watts and can dangerously overheat if overloaded.
Source(s):
Wikipedia: Ohm's Law
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February 15, 2009 05:54 AM
A minor issue... you wrote the formula as if it was Amps divided by Watts. (the slash usually means divided by in math terms).. but later in your sentence, you correctly show it as amps times (asterisk) volts (volts*amps) ..
it just creates some minor confusion...
As I mentioned, most engineering teachers (and electricians) try to get students to remember WestVirginia (WVA)
(Watts=Volts*Amps)
Just saying..
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it just creates some minor confusion...
As I mentioned, most engineering teachers (and electricians) try to get students to remember WestVirginia (WVA)
(Watts=Volts*Amps)
Just saying..
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W=V*A (Some people remember this as West Virginia W-VA)
watts= volts X amps