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M$1.00  Funded By Mahalo ? |  March 06, 2009 01:53 AM

Does (n+2)/(n+1) converge or diverge as n approaches infinity? Integral of this is ....

Integral of it is x*ln(x+1), which diverges if you plug in infinity for x, but I wasn't entirely sure and wanted someone to check it.
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March 06, 2009 02:00 AM
(n+2)/(n+1) converges as n tends to infinity.

It gets arbitrarily close to 1 without ever getting there. If you needed to do a formal proof, you would show that for any value epsilon>0, there exists N such that for all n>N, (n+2)/(n+1) differs from 1 by less than epsilon.

The integral of (n+2)/(n+1) diverges becauses it's adding up an infinite series of numbers all of which are greater than 1.


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March 08, 2009 05:58 AM
If you multiply the top and bottom by 1/n (effectively multiplying by 1) and you get (1 + 2/n)/(1 + 1/n), you can see that as n approaches infinity, you get 1/1, or just 1.

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