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cucumber

M$1.00 Funded By Mahalo ? | April 27, 2009 05:40 AM

What is the integral of 1/5 e ^ (-x/5)

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howuliketh...

April 27, 2009 08:49 AM

assuming you mean (1/5) e^(-x/5) and not 1/(5e^(-x/5)),

integram ((a*e^(bx) ) = (a/b)e^(bx) + C where C is a constant

so, a = 1/5
b= (-1/5)

so integral = -e^(-x/5) + C

Asker's Rating:

• Thank You very much. I thought I had the answer right but has been 20 years since calc 2 and I rarely need more than quadratics. It's been so long that I wasn't sure I was following the explanations I found online how to do this right.

Joe

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