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The sum squares of two numbers are 68 and the square of their difference is 36. The product of the two numbers is?
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Given,
(a +b) to the power 2 = 68
(a - b) to the power 2 = 36
therefore, (according to the algebraic formula)
( a + b )2 = a2 + 2ab + b2 = 68 (equation 1)
(a - b)2 = a2 - 2ab + b2 = 36 (equation 2)
by subtracting equ 2 from equ 1 we get
4 ab = 32
therefore ab (a * b) = 32 / 4 = 8
the product of two numbers is a, b is 8.
(a +b) to the power 2 = 68
(a - b) to the power 2 = 36
therefore, (according to the algebraic formula)
( a + b )2 = a2 + 2ab + b2 = 68 (equation 1)
(a - b)2 = a2 - 2ab + b2 = 36 (equation 2)
by subtracting equ 2 from equ 1 we get
4 ab = 32
therefore ab (a * b) = 32 / 4 = 8
the product of two numbers is a, b is 8.
Voted as best: twinpairs, tealmyster
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