Divisibility test for 17 and 29
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M$2 Answers
Subtract five times the last digit from the remaining leading truncated number. If the result is divisible by 17, then so was the first number. Apply this rule over and over again as necessary.
Example: 3978-->397-5*8=357-->35-5*7=0. So 3978 is divisible by 17."
"Test for divisibility by 29:
Add three times the last digit to the remaining leading truncated number. If the result is divisible by 29, then so was the first number. Apply this rule over and over again as necessary.
Example: 15689-->1568+3*9=1595-->159+3*5=174-->17+3*4=29, so 15689 is also divisible by 29."
Both quoted from source. It's pretty interesting that there exists tests for these numbers! Happy dividing!
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M$adj.
Capable of being divided, especially with no remainder: 15 is divisible by 3 and 5." (this information was taken from http://www.thefreedictionary.com/Divisibility)
Dividing by 3
1. Add up all the digits in the number.
2. Find out what the sum is. If the sum is divisible by 3, so is the number
3. For example: 12123 (1+2+1+2+3=9) 9 is divisible by 3, therefore 12123 is too!
15 can be divided hence it is divisible (numbers that can divide 15 are 3 and 5)
29 cannot be divided by other numbers except it self hence it is not divisible
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