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M$2.00  Funded By Mahalo ? |  April 17, 2009 04:25 PM

I need 2 methods,at least, for solving this expression:
sin 15 + sin 75!

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April 27, 2009 06:04 AM
One is to just calculate the sin of each - you might need to use the formulas for half angle (15 degrees is half of 30, sin30= .5)

Another is to note that the sin 75 = cos 15 (since 15 = 90-75), So sin15 + sin 75 = sin 15 + cos 15. You might then need to use the trig values of 30 degrees, and the equations for the sin and cos of half-angles (where 15 degrees of course is half the 30-degree angle).

A list of trig functions are here:

http://www.sosmath.com/trig/Trig5/trig5/trig5.html


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May 25, 2009 12:37 AM
sin(15 deg )+sin(75 deg ) = (-e^(-15 deg i)+e^(15 deg i))/(2 i)+(-e^(-75 deg i)+e^(75 deg i))/(2 i)
or
sin(15 deg )+sin(75 deg ) = 1/(sec(-75 deg +pi/2))+1/(sec(-15 deg +pi/2))
Work as well

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